QUESTIONIn a dual-loop fire detection system with automatic self-interrogation, the control circuit of one loop signals fire and the self-interrogation circuit then tests the other loop and finds it operative. What does the system do?
- AOutputs a fire warning based on the one loop alone
- BSuppresses the fire signal from the single loop
- CDisconnects both loops and shows a fault message
Show the answer and explanation
Correct answer: B. Suppresses the fire signal from the single loop
- A — incorrect A fire signal is output from a single loop only when the interrogation finds the other loop inoperative.
- B — correct If the other loop tests operative, the circuit suppresses the fire signal, because an operative loop would also have signaled if a fire actually existed.
- C — incorrect Self-interrogation exists to eliminate the fault indication and keep detection available; it does not shut the system down.